Bogomoev and Lomtadze to fight for gold in freestyle wrestling

Read on the website Vestnik Kavkaza

Alexander Bogomoev (Russia) defeated Haji Aliyev (Azerbaijan) with the score of 3:1, Beka Lomtadze (Georgia) defeated Radoslav Velikov (Bulgaria) with a score of 4:0. So, Alexander Bogomoev and Beka Lomtadze will meet in the category up to 61 kg at 17:14 (MSK).

Haji Aliyev will compete for the bronze medal with Munir Recep Aktas (Turkey).